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wariber [46]
3 years ago
10

Help!! i'll give brainliest

Mathematics
2 answers:
otez555 [7]3 years ago
6 0

Answer:

Im pretty sure D

Step-by-step explanation:

solmaris [256]3 years ago
3 0
The answer is D. because the y intercept is 3 and the slope is down 1 and over 2.
hope this helps.
Brainliest please!
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Please help thank you!
kotegsom [21]

Answer:

Note that PQ + QR = PR:

Once:  

PR = 15x-11\\PQ=3x+6

PQ + QR = PR\\\\(3x+6)+QR=(15x-11)\\\\QR=(15x-11)-(3x+6)\\\\QR=15x-11-3x-6\\\\QR=12x-17\\

Therefore, the answer is letter B

8 0
3 years ago
If c = 4, evaluate the following expression: <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bc%7D%20" id="TexFormula1" title=
mash [69]

Answer:

2 is the answer

Step-by-step

6 0
2 years ago
3. Which property justifies rewriting
Maksim231197 [3]
B distributive property
7 0
3 years ago
What is the standard form for the quadratic function?<br>f(x) = (x – 3)2 + 5​
Minchanka [31]

Answer:

f(x)  = x² - 6x + 14

Step-by-step explanation:

Standard form is ax² + bx + c = 0 or f(x) = ax² + bx + c

So we are going to expand the equation and combine like terms:

f(x) = (x - 3)² + 5

f(x) = x² - 3x - 3x + 9 + 5

f(x) = x² - 6x + 9 + 5

f(x) = x² - 6x + 14

7 0
3 years ago
Find the linear equation of the plane through the origin and the points (5,2,2) and (6,−1,1). equation:
Aleks [24]
The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane

Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
3 0
4 years ago
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