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3 years ago

235 acres, or 15%, of a forest is being logged. How large is the forest?

Mathematics

2 answers:

Leto [7]3 years ago

8 0

The forest is 1566.7 acres

0.15x = 235

<span>x = 235/0.15 </span>

<span>x = 1566.7 </span>

Gre4nikov [31]3 years ago

3 0

15 % is equivalent to 235 acres
100 % will be equivalent to?
$\frac{100*235}{15}$
=1566.77acres

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Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?

Flauer [41]

Answer:

The m∠D is 98° ⇒ answer D

Step-by-step explanation:

* Lets revise some facts in the circle

- The quadrilateral is inscribed in a circle if its four vertices lie on the

circumference of the circle

- It is called a cyclic quadrilateral

- Every two opposite angles in it are supplementary means the

sum of their measures is 180°

∵ ABCD is inscribed in a circle

∴ ABCD is a cyclic quadrilateral

∵ ∠A and ∠C are opposite angles in the cyclic quadrilateral ABCD

∴ ∠A and ∠C are supplementary

∴ m∠A + m∠C = 180°

∵ m∠A = 64°

∵ m∠C = (9x - 1)°

∴ 64 + (9x - 1) = 180 ⇒ simplify

∴ 63 + 9x = 180 ⇒ subtract 63 from both sides

∴ 9x = 117 ⇒ divide both sides by 9

∴ x = 13

- Lets find the measure of ∠B

∵ m∠B = (6x + 4)°

∵ x = 13

∴ m∠B = 6(13) + 4 = 78 + 4 = 82°

- Lets find the measure of ∠D

∵ ∠B and ∠D are opposite angles in the cyclic quadrilateral ABCD

∴ ∠B and ∠D are supplementary

∴ m∠B + m∠D = 180°

∵ m∠B = 82°

∴ 82° + m∠D = 180° ⇒ subtract 82° from both sides

∴ m∠D = 98°

* The m∠D is 98°

3 0

4 years ago

HELP! PLEASE! Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25

Misha Larkins [42]

Answer:

Part A) $A=1.25W^2$

Part B) Length: 17.5 feet and Width: 14 feet

Step-by-step explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the rectangular basketball section

W ---> the width of the rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

$A=LW$ ----> equation A

The length of the section will be 1.25 times the width of the section

$L=1.25W$ ----> equation B

substitute equation B in equation A

$A=(1.25W)W\\A=1.25W^2$

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

$A=1.25W^2\\A=245\ ft^2$

$245=1.25W^2$

solve for W

$W^2=245/1.25\\W^2=196\\W=14\ ft$

Find the value of L

substitute the value of W in the equation B

$L=1.25(14)=17.5\ ft$

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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14. The range of the data 6, 8, 16, 22, 8, 20, 7, 25 is __________.

maks197457 [2]

Answer:

The range of the data is 19.

Step-by-step explanation:

To solve this problem, we must remember that to calculate the range, we subtract the smallest data point in the set from the largest data point. In this case, the largest number is 25 and the smallest number is 6.

Therefore the range is:

25 - 6

= 19

Hope this helps!

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4 years ago

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