It is in form
0=ax^2+bx+c
0=-3x^2-2x+6
a=-3
b=-2
c=6
so
x=
x=
x=
x=
x=
x=
x= or
Point slope form is
Y-y1=m(x-x1)
-in this^ u only should put number in the y1, m, and x1
-m is your slope
Slope intercept form is
Y=mx+b
-start out with putting numbers in m and b and then you'll find your way to your y and x
3/18 because what you do to the denominator, you do to the numerator. Since 6x3 is 18, 1x3 is 3.
Consider the equation
.
First, you can use the substitution
, then
and equation becomes
. This equation is quadratic, so
.
Then you can factor this equation:
.
Use the made substitution again:
.
You have in each brackets the expression like
that is equal to
. Thus,
![x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=%20x%5E3%2B5%3D%28x%2B%5Csqrt%5B3%5D%7B5%7D%29%28x%5E2-%5Csqrt%5B3%5D%7B5%7Dx%2B%5Csqrt%5B3%5D%7B25%7D%29%20%2C%5C%5Cx%5E3%2B1%3D%28x%2B1%29%28x%5E2-x%2B1%29%20%20%20)
and the equation is
.
Here
and you can sheck whether quadratic trinomials have real roots:
1.
.
2.
.
This means that quadratic trinomials don't have real roots.
Answer:
If you need complex roots, then
.
Answer:
4x-6y-12=0 than it passes through the origin so.distance equals /ax+by+c/all over a^2+ b^2= 4(0)+6(0)-12/4^2+6^2= -12/16+36=12/52=0.23077