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kherson [118]
4 years ago
8

Nitrogen:0.781 oxygen:0.209 argon: 0.010 (Mole fraction)

Chemistry
1 answer:
horrorfan [7]4 years ago
8 0

Answer:

The partial pressure of nitrogen is 597.5 torr

Explanation:

Step 1: Data given

Mol fraction of N = 0.781

Mol fraction of O = 0.209

Mol fraction Ar = 0.010

Atmospheric pressure = 765.0 torr

The partial pressure is given by  Pi = Xi * Pt

⇒ χ i  =  the mole fraction of gas  i  in the mixture

⇒ P total  = the total pressure of the mixture

Step 2: Calculate the partial pressure of nitrogen

P(N) = mol fraction of N * atmospheric pressure

P(N) = 0.781 * 765.0 torr = 597.5 torr

The partial pressure of nitrogen is 597.5 torr

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