Answer:
Percent yield = 57.8 %
Theoretical yield = 11.781 g
Explanation:
Given data:
Mass of CaO produced = 6.81 g
Mass of CaCO₃ react = 20.7 g
Theoretical yield = ?
Percent yield = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaCO₃ :
Number of moles = mass/molar mass
Number of moles = 20.7 g/ 100.1 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of CaCO₃ with CaO.
CaCO₃ : CaO
1 : 1
0.21 : 0.21
Theoretical yield of CaO:
Mass = number of moles × molar mass
Mass = 0.21 mol × 56.1 g/mol
Mass = 11.781 g
Percent yield:
Percent yield = ( actual yield / theoretical yield ) × 100
Percent yield = (6.81 g/ 11.781 g) × 100
Percent yield = 57.8 %
Answer:
b). It will have only one isoionic point which is found below pH = 7.0. c). It will be fully protonated at pH = 1.0 with a net charge of +2. d).
Explanation:
Answer:
Why is this statement given me Willy Wonka vibes
Explanation:
The mass per volume of a substance is called its density.
Answer:
Explanation:
To make a distinction in favor of or against a person or thing on basic or group, class or category, to which the person or thing(s) belong
