I got you
The molecular formula for the combustion of butane in oxygen is:
2 C4H10 + 13 O2 ---> 8 CO2 + 10 H20
<span>You take the mass of carbon dioxide, 56.8g, divide by its molar mass, 44.01g/mol, to produce the moles of carbon dioxide. This is multiplied by the molar ratio of butane/CO2, (2/8) = 1/4, which gives the moles of butane required to produce the carbon dioxide. Multiply the number of moles of butane by its molar mass, 58.12g/mol, to produce the mass of butane. Mass of butane = 18.8g</span>
The correct answer is D Elements
Mass of Al₂(SO₄)₃ : 4.822 g
<h3>Further explanation </h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl
MW AlCl₃ :133,34 g/mol
MW (NH₄)₂SO₄ : 132,14 g/mol
MW Al₂(SO₄)₃ : 342,15 g/mol
mol AlCl₃

mol (NH₄)₂SO₄

Limitng reactants (ratio mol : coefficient = the smaller)
AlCl₃ : (NH₄)₂SO₄ =

(NH₄)₂SO₄ ⇒ limiting reactants
So mol Al₂(SO₄)₃ from (NH₄)₂SO₄

mass Al₂(SO₄)₃

with 54.2% yield, the mass of Al₂(SO₄)₃

Answer:
is there choices you have to pick from
Explanation:
or do you have to describe a covalent bond ?