The rule that represents the height of the ball after each bounce is;
H(n) = 400(0.8)^(n - 1)
<h3>Geometric Sequence Progression</h3>
From online sources, we have that;
After first bounce, height = 400 m
After 2nd bounce, height = 320 m
After 3rd bounce, height = 256 m
Formula for the nth term of a geometric sequence is;
T_n = ar^(n - 1)
First term is 400m
Since second term is 320, then common ratio is;
r = 320/400
r = 0.8
Thus, the 6th bounce which is the 6th term will be;
T_6 = 400 * 0.8^(6 - 1)
T_6 = 131 m
Read more about geometric sequence at; brainly.com/question/21688964
If the x goes after (1-) then it’s going to be x=-4
The carrot patch is a 2 by 5 rectangle so 2 times 5 is 10 so the answer is A
Answer:
a. 22.08 
Step-by-step explanation:
d = diameter = 15ft; r = (1/2)d = 7.5ft; A=area
So, A = (π) × 
A = (π) × 
A = (π) × 
The entire circle is 360°, so 45 is 
.
A(slice) = 
× 
π
A(slice) = 7.03 × (π) ×
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1) cos (150°)=- cos(180°-150°) = - cos(30°) and - cos30° = - √(3) / 2
sin(150°) = sin(180°-150°) =sin30. and sin30° = 1/2
Then : 5/2(cos 150° + i sin 150°) becomes : 5/2{(-√(3) /2 + I (1/2)]
OR 5/4( - √3 + i)
