Question

A motorist drives north for 35.0 min at 85.0 km/h and then stops for 15.0 min. He then continues north, traveling 130 km in 2.00 h. (a) what is his total displacement? b) what is his average velocity?

Answer 1

Answer:

(a) Total displacement will be 176.666 km

(b) Average velocity will be 62.3534 km/hr

Explanation:

We have given a motorist drive for 35 minutes at 85 km/hr

We know that 1 hour = 60 minutes

So $35\ minutes=\frac{35}{60}=0.5833hour$

So distance covered in 35 minutes = 0.5833×80 = 46.666 km

After he stops for 15 minutes that is 0.25 hour

Then he travel 130 km in 2 hour

(a) So total displacement = 130+46.666 = 176.666 km

(b) Total time t = 0.5833 +0.25 +2 = 2.8333 hour

Average velocity is given by $average\ velocity=\frac{total\ distance}{total\ time}=\frac{176.666}{2.8333}=62.3534km/hr$