A ladybug falls into small hole. it takes 8.6s for the ladybug to hit the bottom. how deep is the hole? (take g=9.81 m/s²)

compare the magnitude and range of the four basic forces—gravitational, electromagnetic, weak nuclear and strong nuclear

Andrews [41]

Answer:

The four fundamental forces magnitude and range are in order of Strong Nuclear Force > electromagnetic force > weak nuclear force > gravitational force.

Explanation:

The 4 fundamental force are weak nuclear force, strong nuclear force, em force and the gravitational force are discussed below.

Strongest force is the strong nuclear force as compared to all of them. It is very useful for capturing the atoms nucleus together despite the large repulsion which is occur between the same charges due to protons in the nucleus.

Electromagnetic Force is the 2nd strongest fundamental force. Magnetism and electricity was thought to be of 2 separate forces.

Weak Nuclear Force involves the W and Z bosons exchange. It has a very short range of

Gravitational Force is the weakest between all the fundamental forces. However, due to its long range it is the most dominant force. It follows the inverse square law like but it is always attractive in nature.

6 0

3 years ago

Which of the following is not something that the atmosphere does for us?

Masja [62]

Tha atmosphere has no effect on gravity.

4 0

3 years ago

Read 2 more answers

How are some types of collisions different from others?

lyudmila [28]

There are two general types of collisions, inelastic and elastic.
Inelastic collisions occur when two objects collide but neither of them bounce away from each other.
Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering)

3 0

3 years ago

A solenoidal coil with 25 turns of wire is wound tightly aroundanother coil with 300 turns. The inner solenoid is 25.0 cm long a

Aneli [31]

Answer:

(a). The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Explanation:

Given that,

Number of turns of coil = 25

Number of turns of another coil = 300

Length = 25.0 cm

Diameter = 2.00 cm

Current = 0.120 A

Rate $\dfrac{di_{2}}{dt}=1.75\times10^{3}\ A/s$

(a). We need to calculate the magnetic field due to inner solenoid

Using formula of magnetic field

$B=\mu_{0}(\dfrac{N_{2}}{l})I$

Put the value into the formula

$B=4\pi\times10^{-7}\times(\dfrac{300}{0.25})\times0.120$

$B=1.81\times10^{-4}\ T$

We need to calculate the average magnetic flux through each turn of the inner solenoid

Using formula of magnetic flux

$\phi=B\cdot A$

Put the value into the formula

$\phi=1.81\times10^{-4}\times\pi\times (1.00\times10^{-2})^2$

$\phi=5.68\times10^{-8}\ Wb$

The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). We need to calculate the mutual inductance of the two solenoids

Using formula of mutual inductance

$M=\dfrac{N_{1}\phi}{i_{1}}$

Put the value into the formula

$M=\dfrac{25\times5.68\times10^{-8}}{0.120}$

$M=0.00001183\ H$

$M=1.183\times10^{-5}\ H$

The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). We need to calculate the emf induced in the outer solenoid by the changing current in the inner solenoid

Using formula of emf

$\epsilon=-M\dfrac{di_{2}}{dt}$

Put the value into the formula

$\epsilon=-1.183\times10^{-5}\times1.75\times10^{3}$

$\epsilon=-0.0207\ V$

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

Hence, (a). The average magnetic flux through each turn of the inner solenoid is $5.68\times10^{-8}\ Wb$

(b). The mutual inductance of the two solenoids is $1.183\times10^{-5}\ H$

(c). The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.0207 V.

5 0

3 years ago

Please show all the steps and work. The answer is -3.9 m/s2

konstantin123 [22]

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0^2-66^2}{2(560)}\\\\a=-3.9\ m/s^2$

Therefore, the acceleration of the airplane is $-3.9\ m/s^2$

8 0

3 years ago