Question

Due in 30 help me please ​

Answer 1

Answer:

1. Fc = 14212.3 N = 14.21 KN

2. ac = 1579.14 m/s²

Explanation:

First, we  will find the linear velocity of the ball:

$v = r\omega$

where,

v = linear velocity = ?

r = radius of circle = 2.5 m

ω = angular speed = (4 rotations/s)(2π rad/1 rotation) = 8π rad/s

Therefore,

$v = (2.5\ m)(8\pi\ rad/s)\\v = 62.83\ m/s$

2.

Now, the centripetal acceleration can be given as:

$a_{c} = \frac{v^2}{r}$

where,

ac = centripetal acceleration = ?

Therefore,

$a_{c} = \frac{(62.83\ m/s)^2}{2.5\ m}$

ac = 1579.14 m/s²

1.

The centripetal force can be given as:

$F_{c} = ma_{c}\\F_{c} = (9\ kg)(1579.14\ m/s^2)$

Fc = 14212.3 N = 14.21 KN