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3 years ago

15

What are the more appropriate measures of center and spread for this data set? 5 8 10 14 24

2 answers:

Dima020 [189]3 years ago

6 0

Answer:

<h2>B. Better measure of center: the median.</h2><h2>D. Better measure of spread: the interquartile range (IQR).</h2>

Step-by-step explanation:

The median is a measure of central tendency. Specifically, it indicates the central value of a data set, the value that is at the exact center, that is the median. That's why the median is the best measure of center for a data set.

On the other hand, the interquartile range is the difference between the first quartile and the third quartile, that is, the first and last quartile, this difference represent better the spread, because it shows the variability of the data set. This variability measure makes the interquartile range the best option of represent spread.

julia-pushkina [17]3 years ago

5 0

Answer:

B. and D. is the answer.

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A small boat can travel at 28 per hour how many hours will it take to go across the bay that is 56 miles wide

dsp73

Answer:

2 hours

Remember that time = distance/rate

The distance you need to cover is 56 miles, while you go 28 miles per hour. Using these, we get this:

time=56/28

time=2

So it will take two hours to go across a 56 mile wide bay at 28 mph.

Step-by-step explanation:

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3 years ago

Geometry help?<br> 24/10<br> 10/24<br> 24/26<br> 10/26

olasank [31]

24/26 or opposite over adjacent. The answer is C

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3 years ago

The sum of nine-tenths and g is two-thirds solve for g

Naya [18.7K]

Answer:

- 7/30

Step-by-step explanation:

9/10 + g = 2/3

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3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

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3 years ago

SOOO CLOSEE TO BEING DONEEEE helppppp

grandymaker [24]

$423 \times 10 {}^{2}$

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4 0

2 years ago

Read 2 more answers