Find the Greatest Common Factor (GCF)
<u>GCF = 6y^6</u>
Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)
6y^6(24y^8/6y^6 + 6y^6/6y^6)
Simplify each term in parenthesis
<u>6y^6(4y^2 + 1)</u>
5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
Step-by-step explanation:
Given bi-quadratic equation is:
Substituting 
given bi-quadratic equation reduces in the form of following quadratic equation:
Let us factorize the above quadratic equation:
Since square root of a negative number cannot be found, so:
Answer:
Step-by-step explanation:
Let “x” be the weight of the bottle and “y” is weight of honey.
We know the total weight of bottle full of honey is 1000 g.
So Equation 1 is x + y = 1000 g
And with half of the honey, we know the total weight is 600g.
Equation 2: x + (y/2) = 600 g
y/2=600 - x
y= 2 (600 - x)
y= 1200 - 2x
We can replace “y” with 1200 - 2x in Equation 1:
x + 1200 - 2x = 1000
x = 200 g
Weight of the bottle is 200 g.
Answer:
15
Step-by-step explanation:
