An <u>example of a problem</u> where I <em>would not</em> group the addends differently is:
3+2+4.
An <u>example of a problem</u> where I <em>would</em> group the addends differently is:
2+5+8.
Explanation:
In the <u>first problem</u>, I would not group the addends differently before adding. This is because I cannot make 5 or 10 out of any of the numbers. We group addends together to make "easier" numbers for us to add, such as 5 and 10. If we cannot do that, there is no reason to regroup the addends.
In the <u>second problem</u>, I would regroup like this:
2+8+5
This is because 2+8=10, which makes the problem "easier" for us to add. Since we can get a number like this that shortens the process, we can regroup the addends.
Answer:
3x^2+3x+2
using Euclid's division algorithm
you can verify itt...
6 it is the same as the other I think
Answer:1/6
Step-by-step explanation: So you toss it 3 times(1/3) and you have 50% chance(1/2) of choosing heads or tails... so,
1/3 x 1/2 = 1/6
81 divided by 37.5 equals 2.16, 2.16 would be equivalent to 1% so to find 100% we simbly multiply 2.16 by 100, 2.16 multiplied by 100 equates to 216, so the Baker is making 216 muffins.
If this is a word problem, put it into your own words in case of getting in trouble.
I hope this helped, have an awesome day!!
(brainliest is always appreciated)
