A can of tuna has a diameter of 4 inches and a height of 3 inches. what is the volume of the can of tuna?
2 answers:
V=r^2(pi)h, D=4 so r=2, V=4(3)(pi)=12(pi) or 37.699 inches^3.
Volume of a cylinder = πr^2h
π(2)^2(3)
12π
v=37.68 inches cubed
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