Answer:
Explanation:
The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.
The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

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Answer:
(0.6430, 0.8170)
Step-by-step explanation:
Given that during a recent drought a water utility in a certain town sampled 100 residential water bills and found out that 73 of the residences had reduced their water consumption over that of the previous year.
Sample size n = 100
Sample proportion p = 
q = 1-p = 0.23
Std error of proportion = 
95% Z critical value = 1.96
Margin of error = 
Confidence interval = sample proportion ±margin of error
0.642983946
0.817016054
(0.6430, 0.8170)