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Ludmilka [50]
2 years ago
8

Mr. Wing is purchasing a new computer that costs $2,376. There is no interest charge if it is paid for in the next 12 months. Ho

w much will he need to pay monthly to avoid interest charges? a. $114.67 c. $189.67 b. $198 d. $200
Mathematics
2 answers:
4vir4ik [10]2 years ago
8 0

Answer:

B. 198

Step-by-step explanation:

Vedmedyk [2.9K]2 years ago
6 0

Answer: $198

Step-by-step explanation:

2376/12 = 198

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Triangle ABC has side lengths:
Nat2105 [25]
ABC and HJK are congruent and the corresponding sides and angles are equal. Side HJ is congruent with side AB so HJ is also 3.5cm in length.
8 0
3 years ago
Read 2 more answers
Ms. Jackson emptied 16 boxes of crayons into a classroom crayon bucket in each box 2/9 The crayons were green how many crayon bo
mote1985 [20]

Answer:

2 boxes

Step-by-step explanation:

do 16 times 2 you get 32 so there are 32 green crayons 32/9 9 times 3 is 36 which is over 32 so you cant fill 3 boxes 9 times 2 equals 27 so the answer would be she can fill 2 boxes

5 0
3 years ago
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HELP!
Alexxx [7]

Answer:

LIMIT

The policy will pay for up to

$100,000 of damage to

another person's property.

The policy will pay only

$100 per incident for a

tow truck

DEDUCTIBLE

The policyholder must pay

the first $1,000 of repair

expenses before insurance

will pay for anything,

PREMIUM

The policy offers coverage

for a cost of $178 per month

The policyholder must

pay $500 semiannually

to the insurance provider

Step-by-step explanation:

LIMIT is the maximum amount an insurer will pay toward a covered claim

DEDUCTIBLE is the amount paid out of pocket toward a covered claim

PREMIUM is the amount paid regularly to keep the policy in force.

6 0
2 years ago
M x+ B = y solve for B <br><br><br> A x+ B y = C solve for x <br><br><br> Bh/2 = A, solve for h
quester [9]

Step-by-step explanation:

Mx+B=y

B=y-Mx

Ax+By=C

Ax=C-By

Ax/A=C-By/A

x=C-By/A

Bh/2=A

2 x Bh/2=A x 2

Bh=2A

Bh/B=2A/B

h=2A/B

5 0
3 years ago
Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod
goblinko [34]

(2+3)^{-1}\equiv5^{-1}\pmod7 is the number <em>L</em> such that

5L\equiv1\pmod7

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

2a\equiv1\pmod7\implies a\equiv4\pmod7

since 2*4 = 8, whose residue is 1 mod 7;

3b\equiv1\pmod7\implies b\equiv5\pmod7

which we got for free by finding the inverse of 5 earlier. So

2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0
3 years ago
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