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2 years ago

8

Mr. Wing is purchasing a new computer that costs $2,376. There is no interest charge if it is paid for in the next 12 months. Ho

w much will he need to pay monthly to avoid interest charges? a. $114.67 c. $189.67 b. $198 d. $200

2 answers:

4vir4ik [10]2 years ago

8 0

Answer:

B. 198

Step-by-step explanation:

Vedmedyk [2.9K]2 years ago

6 0

Answer: $198

Step-by-step explanation:

2376/12 = 198

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A building contractor is to dig a foundation 30 feet long, 12 feet wide, and 6 feet deep. The contractor pays $20 per load fo

kogti [31]

Answer:

$1800

Step-by-step explanation:

Volume of the foundation: 30*12*6 = 2160 cubic feet

we need to convert this into yards because a truckload is 8 cubic yards, 2160/3 = 720 cubic yd

One truckload is 8 cubic yards

# of truckloads needed: 720/8 = 90 truckloads

Cost: $20*90 = $1800

3 0

1 year ago

F(x)=x2+8x+6. What is the value of f(4)?

dezoksy [38]

46

When it says f(4) that means x=4

So you then just fill in all the x’s with 4’s and solve as normal

4 0

2 years ago

Find the distance between a and b.<br><br> <br><br> a = 9.21, b = –5.51<br><br>

cricket20 [7]

9.21 - (-5.51)
9.21 + 5.51 = 14.72
The distance is 14.72

5 0

3 years ago

Read 2 more answers

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

2 years ago

For the two right triangles above, explain why

Korvikt [17]

Answer:

we cant see the triangles

Step-by-step explanation:

5 0

2 years ago