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Answer: Margin of error = 6.58
Confidence interval = (26.91, 40.08)
Step-by-step explanation:
Since we have given that
Sample size n = 8
Sample mean = 33.5 minutes
Population standard deviation = 9.5 minutes
At 95% confidence interval,
α = 0.05
t = 1.96
So, Margin of error is given by
Confidence interval would be
Lower limit:
Upper limit:
Hence, the interval would be (26.91, 40.08)
But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)
Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.