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slava [35]
3 years ago
12

If i was born in 1996 how old am i in 2017

Mathematics
2 answers:
o-na [289]3 years ago
5 0
If I was born in 1996 in 2017 i am 21 years old.
From year 1996 to year 2006 there are 10 years.
From year 2006 to year 2016 there are 10 years.
-> From year 1996 to year 2016 there are 10 + 10= 20 years.
And from year 2016 to year 2017 there is 1 year.
So, 10+10+1=21 years will pass from 1996 till 2017.
Irina18 [472]3 years ago
5 0

Answer:

21 years will pass from 1996 until 2017.

2017-1996 = 21 years

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The first term of an Ap are x, 2x +1, and 5x+1 Find<br> x and the sum of the<br> l0 terms<br> first
bazaltina [42]

Answer:

145/2

Step-by-step explanation:

d=[2x+1-x] = [5x+1 -(2x+1)]

x+1=3x

x-3x=-1

-2x=-1

x=1/2

therefore first term is 1/2

second term is 2(1/2)+1= 2

common difference d is 2-1/2=3/2

sum of first n terms is n/2 [2a+(n-1)d] where n=10

sum of first 10 terms= 10/2[2×1/2+(10-1)3/2]

=5[1+(9)3/2] =5[1+27/2] = 5[29/2] =145/2

7 0
3 years ago
Need Help Please!!!!
denis-greek [22]

Answer:

4ab and 3ab

Step-by-step explanation:

4<em>ab</em> and 3<em>ab</em> because they have the same variables <em>a</em> and <em>b</em>

4 0
2 years ago
A sound wave enters a new medium where sound travles faster. How does this affect the frequency and wavelength of the sound?
zhenek [66]

Answer:

The frequency doesn't change. If the wavespeed increases, then the wavelength must also increase ... It's just the distance the wave travels during each complete wiggle.

Step-by-step explanation:

  • Sound waves are a type of mechanical wave which requires a material medium for transmission. The transmission of such waves occurs as a result of vibration of particles in the material medium. The faster the vibration of the particles the higher the speed of the sound waves.
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4 0
3 years ago
How do i solve this equation
dedylja [7]
The first step to solving this is to multiply both sides of the equation by 3
8 + 10y = 9y - 12
now move the variable to the left side and change its sign
8 + 10y - 9y = -12
move the constant to the right side and change its sign
10y - 9y = -12 - 8
collect the like terms for y
y = -12 - 8                  (it equals 1 when you subtract 10 from 9 which is the same is simply saying "y")
calculate the difference on the other side of the equals sign
y = -20
this means that the correct answer to your question is -20.
let me know if you have any further questions
:)
6 0
2 years ago
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
2 years ago
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