Answer:Short circuit, closed circuit, open circuit
Answer:
A: b^3. B. X^3
Step-by-step explanation:
When dividing subtract the exponents is the property.
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
Answer:
d
Step-by-step explanation:
x<9+7, and x+7>9
solve
x<16
x>2
2<x<16
<span>square root of 25 is the correct answer</span>
