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Bond [772]
3 years ago
8

james has a piece of construction paper with an area of 65 1/4 inches is 9 2/3 inches long. What is the width of a piece of cons

truction paper in inches. Can you me what i do with answer?
Mathematics
2 answers:
Mashcka [7]3 years ago
7 0

Answer:

6.75 in

Step-by-step explanation:

We are given that

Area of piece of construction paper=65\frac{1}{4} in^2=\frac{261}{4} in^2

Length of piece of construction paper=9\frac{2}{3} in=\frac{29}{3}in

We have to find the width of a piece of construction paper.

Width of rectangle =\frac{Area}{length}

Width of  piece of construction paper=\frac{\frac{261}{4}}{\frac{29}{3}}

Width of  piece of construction paper=\frac{261}{4}\times \frac{3}{29}=\frac{27}{4}=6.75in

Hence, width of  piece of construction paper=6.75 in

Aneli [31]3 years ago
3 0
  • divide 65 1/4  with 9 2/3 you will get 6 3/4.
  • so width is 6 3/4
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h=404.89

Step-by-step explanation:

We are looking for side h, which is opposite of the observer. We know that the side adjacent to the observer is 500 feet. We also know that the angle from the observer to the bird is 39°. Because we have these values, SOH CAH TOA tells us that we should use tangent, opposite over adjacent.

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Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu
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Answer:

z(s)  is in the rejection zone , therefore we reject H₀

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We have a prortion test.

P₀  =  37 %         P₀  = 0,37

sample size  =  n  =  100

P sample proportion   =   P  = 47 %        P  =  0,47

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α  =   0,05  

One tail-test  (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀      null hypothesis                        P₀  =  0,37

Hₐ  alternative hypothesis                P₀  >  0,37

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z(s)  =  [  P  -  P₀  ]  /√(P₀Q₀/n) ]  

z(s)  =  [ (  0,47  -  0,37  ) /  √0.37*0,63/100

z(s)  = 0,1 /√0,2331/100     ⇒   z(s)  = 0,1 /0,048

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5.-Decision:

z(s)  is in the rejection zone , therefore we reject H₀

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