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Bond [772]
3 years ago
8

james has a piece of construction paper with an area of 65 1/4 inches is 9 2/3 inches long. What is the width of a piece of cons

truction paper in inches. Can you me what i do with answer?
Mathematics
2 answers:
Mashcka [7]3 years ago
7 0

Answer:

6.75 in

Step-by-step explanation:

We are given that

Area of piece of construction paper=65\frac{1}{4} in^2=\frac{261}{4} in^2

Length of piece of construction paper=9\frac{2}{3} in=\frac{29}{3}in

We have to find the width of a piece of construction paper.

Width of rectangle =\frac{Area}{length}

Width of  piece of construction paper=\frac{\frac{261}{4}}{\frac{29}{3}}

Width of  piece of construction paper=\frac{261}{4}\times \frac{3}{29}=\frac{27}{4}=6.75in

Hence, width of  piece of construction paper=6.75 in

Aneli [31]3 years ago
3 0
  • divide 65 1/4  with 9 2/3 you will get 6 3/4.
  • so width is 6 3/4
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Step-by-step explanation:

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You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us
Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that    

step 1

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

r=10\%=10/100=0.10\\n=4  

substitute in the formula above

A=P(1+\frac{0.10}{4})^{4t}  

A=P(1.025)^{4t}  

Applying property of exponents

A=P[(1.025)^{4}]^{t}  

A=P(1.1038)^{t}  

step 2

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

r=10\%=10/100=0.10  

substitute in the formula above

A=P(e)^{0.10t}  

Applying property of exponents

A=P[(e)^{0.10}]^{t}  

A=P(1.1052)^{t}  

step 3

Compare the final amount

P(1.1052)^{t} > P(1.1038)^{t}

therefore

Find the difference

P(1.1052)^{t} - P(1.1038)^{t} ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0
3 years ago
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