Answer:
c = 18.47
Step-by-step explanation:
This would create a triangle in which the length of the wall would be the missing side. We can use the Pythagorean Theorem to find this:
1.
+
= 
2.
+
= 
3. 25 + 196 = 
4. 221 = 
5.
= c
6. 18.47 = c
44 sq inches, i am so not sure.
Answer:
Step-by-step explanation:
You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.
Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.
Total of scale usage is 2
b) if you have
coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.
Step 1: you narrow down to group of
coins
Step 2: you narrow down to group of
coins
Step 3: you narrow down to group of
coins
...
Step n: Step 1: you narrow down to group of
coin
Answer:
AY = 16
IY = 9
FG = 30
PA = 24
Step-by-step explanation:
<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>
Let us solve the problem
In Δ AFT
∵ Y is the centroid
∵ AP, TI, and FG are medians
→ By using the rule above
∴ Y divides AP at ratio 1: 2 from the base FT
∴ AY = 2 YP
∵ YP = 8
∴ AY = 2(8)
∴ AY = 16
∵ PA = AY + YP
∴ AP = 16 + 8
∴ AP = 24
∵ Y divides TI at ratio 1: 2 from the base FA
∴ TY = 2 IY
∵ TY = 18
∴ 18 = 2
→ Divide both sides by 2
∴ 9 = IY
∴ IY = 9
∵ Y divides FG at ratio 1:2 from the base AT
∴ FY = 2 YG
∵ FY = 20
∴ 20 = 2 YG
→ Divide both sides by 2
∴ 10 = YG
∴ YG = 10
∵ FG = YG + FY
∴ FG = 10 + 20
∴ FG = 30