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gavmur [86]
3 years ago
10

♫ I have a Brainliest♫ Math situation

Mathematics
1 answer:
wel3 years ago
5 0
<span>13 3/4 length board needed 44.4 hours Since you need 5 lengths of 2 Âľ feet boards, multiply 2 Âľ by 5, giving 5 * 2 3/4 = 5 * 11/4 = 55/4 = 13 3/4 So the answer is 13 3/4 although technically, you'll need a board that's longer since the kerf for a saw blade is greater than 0 ( a typical saw kerf is from 1/16" to 1/8" so in reality Philly and Boston will need a board about 1/2" longer than the minimum. For the second problem, subtract the start time from the end time for each days to figure out how many hours Allison worked each day. Then sum up the hours to get the total time Allison worked. For this problem, it's easier to convert AM/PM times to 24 hour time. Basically, keep the AM times the same and add 12 hours to the PM times. So 5:13 PM - 8:03 AM = 17:13 - 8:03 = 9:10 4:49 PM - 7:58 AM = 16:49 - 7:58 = 8:51 4:41 PM - 7:46 AM = 16:41 - 7:46 = 8:55 4:50 PM - 8:23 AM = 16:50 - 8:23 = 8:27 4:32 PM - 7:31 AM = 16:32 - 7:31 = 9:01 Now add up the hours and minutes: 9:10 + 8:51 + 8:55 + 8:27 + 9:01 = 42:144 Since you can't have 144 minutes, divide the minutes by 60 to get hours and add the whole hours to the hours and the remainder will be the minutes. 144 / 60 = 2, remainder 24 So your time worked becomes 44:24 which is 44 + 24/60 = 44.4 hours. Since 44.4 isn't one of the available answers to pick from, I'd recommend talking to your teacher about the error in the problem.</span>
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A 14 foot ladder is placed against a wall. It is placed 5 feet from the base of the wall.
Vladimir [108]

Answer:

c = 18.47

Step-by-step explanation:

This would create a triangle in which the length of the wall would be the missing side. We can use the Pythagorean Theorem to find this:

1. a^{2} + b^{2} = c^{2}

2. 5^{2} + 14^{2} = c^{2}

3. 25 + 196 = c^{2}

4. 221 = c^{2}

5. \sqrt{221} = c

6. 18.47 = c

4 0
3 years ago
50 POINTSSSS!!!
Slav-nsk [51]

44 sq inches, i am so not sure.

3 0
3 years ago
Read 2 more answers
(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf
alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

Total of scale usage is 2

b) if you have 3^n coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.

Step 1: you narrow down to group of \frac{3^n}{3} = 3^{n-1} coins

Step 2: you narrow down to group of \frac{3^{n-1}}{3} = 3^{n-2} coins

Step 3: you narrow down to group of \frac{3^{n-2}}{3} = 3^{n-3} coins

...

Step n: Step 1: you narrow down to group of 3^{n-n} = 3^0 = 1coin

8 0
3 years ago
Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

∵ AP, TI, and FG are medians

→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

∵ FY = 20

∴ 20 = 2 YG

→ Divide both sides by 2

∴ 10 = YG

∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

5 0
3 years ago
Nichole bought a gift for her friend. She
OlgaM077 [116]

Answer:

10 by 5 =50

10 by 5=50

10 by 2=20

10 by 2=20

2 by 5=10

2 by 5=10

100+40+20=160

3 0
3 years ago
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