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Ratling [72]
3 years ago
12

Consider the quadratic equation ax^2+bx+5=0, where a, b, and c are rational and the quadratic has two didstinct zeros if one zor

e is irrational, the other zero is
Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer:

It can either be rational or irrational

Step-by-step explanation:

Given the quadratic equation ax²+bx+5 = 0, to get the zeros of the function, we will factorize the function to have;

ax²+bx = -5

x(ax+b) = -5

x = -5 and ax+b = -5

From the second function we have;

ax+b = -5

ax = -5-b

x = -5-b/a

This shows that the other value of x can be rational or irrational depending on the values of a and b

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C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

  • Binomial Distribution --> P(k)={n\choose k}p^kq^{n-k}
  • P(k) denotes the probability of k successes in n independent trials
  • p^k denotes the probability of success on each of k trials
  • q^{n-k} denotes the probability of failure on the remaining n-k trials
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<u>Given:</u>

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<u>Calculate:</u>

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Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

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