All categories

3 years ago

Help me somebody. I’m lost with this completely

Mathematics

1 answer:

maks197457 [2]3 years ago

3 0

Answer:

48,828,125

Step-by-step explanation:

PEMDAS

P: 5^2 = 25 (25^4*5^3)

E: 25^4 = 390625, 5^3=125 (390625*125)

M: 390625*125=48828125

D: n/a

A: n/a

S: n/a

You might be interested in

Which quadratic equation defines the function that has zeros at − 1/12 and 1/4 ?

Cerrena [4.2K]

$\bf \begin{cases}
x=-\frac{1}{2}\implies &x+\frac{1}{2}=0\\\\
x=\frac{1}{4}\implies &x-\frac{1}{4}=0
\end{cases}
\\\\\\
\left( x+\frac{1}{2} \right)\left( x-\frac{1}{4} \right)=\stackrel{y}{0}\implies \stackrel{FOIL}{x^2+\frac{1}{4}x-\frac{1}{8}}=y$

7 0

4 years ago

Ahmad travelled 1/4 of a journey by Train X, 3/4 of the remainder by Train Y and the remaining 10km by Train Z. a) How far did A

sveta [45]

Hey there! I'm happy to help!

Train X takes out 1/4 of our journey.

Now, we have 3/4 of the journey left.

Train Y takes 3/4 of the last 3/4 of the journey. How much is that, let's just multiply the fractions!

3/4*3/4= 9/16

So, 9/16 of the total journey is done by Train Y.

A fourth of 16/16 is 4/16, so that leaves us with 3/16 left to go.

So, 3/16 of our total distance is equal to 10 km. Let's call our total distance d and set this up as an equation.

3/16d=10

Divide both sides by 3/16.

d= 53 1/3

We also remember that Train Y gave us 9/16 of our total journey, so we can multiply this by our total distance to see how far train Y went.

53 1/3 * 9/16= 30

So, A. Ahmad traveled 30 miles by Train Y and B. his total distance traveled is 53 1/3 miles.

Have a wonderful day and keep on learning! :D

5 0

3 years ago

Describe how to mentally calculate 1/10 of $12.50

ivanzaharov [21]

Mentally your dividing the 12.50 by 10 and then thats 1/10 of it.

6 0

4 years ago

Please help - help a brother out he tryna pass geometry

astra-53 [7]

Not sure about the second question, but for the first one x=21
I’ve never heard of a similarity statement, so sorry about that. Good luck man!

6 0

3 years ago

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc

aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

$E(X)=\sum x_i p_i$

where

$x_i$ are all the possible values that the variable X can take

$p_i$ is the probability that $X=x_i$

Therefore in this problem, the expected value of MIguel's score is given by:

$E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55$

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

$E(X)=4.2$

- Instead, if the long hit fails, the expected value of X is

$E(X)=5.4$

Here we also know that the probability of a successfull long hit is

$p(L)=0.4$

Which means that the probabilty of an unsuccessfull long hit is

$p(L^c)=1-p(L)=1-0.4=0.6$

Therefore, the expected value of X if Miguel chooses the long hit approach is:

$E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92$

In part 1) of the problem, we saw that the expected value for the short hit was instead

$E(X)=4.55$

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0

3 years ago