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krok68 [10]
3 years ago
8

The number of students enrolled at a college is 12,000 and grows 6​% each year. Complete parts ​(a) through ​(e).

Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

the question is not complete. but with the information you gave 6% of 12000 is 720, the number of students increase by 720 each year

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The graph shows the cost of buying tickets to a concert.
-Dominant- [34]

Answer:

305

Step-by-step explanation:

if the unit rate is $30.5 then thats how much it cost per 1 ticket.

To get 10 tickets we have to do x10

30.5 x 10 = 305

4 0
2 years ago
Read 2 more answers
A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th
kykrilka [37]
If it reaches its maximum height a t=3 its velocity must be zero at t=3

dy/dx=0 at t=3

dA/dx=4x+12=24 at t=3 so this does not apply

dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies

dC/dx=-4x-12=-24 at t=3 so this does not apply

dD/dx=-4x-12=-24 at t=3 so this does not apply

dE/dx=-4x-12=-24 at t=3 so this does not apply

So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
3 0
3 years ago
Read 2 more answers
The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack). Suppose we have
Sonbull [250]

The probability solved by binomial distribution that all will survive is 0.8154.

<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

A heart attack patient has a 0.04 percent chance of dying from the attack (i.e., 4 of 100 die of the attack).

What is the likelihood that each of the five patients who experience a heart attack will survive?

We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

Assume for the purposes of this example that the five individuals being examined are unrelated, of the same age, and free of any concomitant disorders.

By binomial distribution,

\begin{gathered}P(0 \text { successes })=\frac{5 !}{0 !(5-0) !} 0.04^{0}(1-0.04)^{5-0} \\P(0 \text { successes })=\frac{5 !}{5 !}(1)(0.96)^{5}=(1)(1)(0.8154)=0.8154\end{gathered}

Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

brainly.com/question/27794898

#SPJ4

6 0
1 year ago
Which statement is true about the value of (6)? A.(6) greater-than 6
Anvisha [2.4K]

Answer:

D. (6) is the distance between 6 and 0, and the distance is negative from 6 to 0

Step-by-step explanation:

(6) means the number exists in the negative state. It is -6.

Option A - As it is -6, it cannot be greater than positive 6. So, it is incorrect.

Option B - As it is -6, it cannot be less than negative 6. So, it is wrong.

Option C - As it is -6, its distance cannot be 0 to 6, and it should not be positive.

Option D - As it is -6, its distance should be negative and the distance is from 6 to 0. Therefore, it is the correct answer.

7 0
3 years ago
Zach invested $1500. He earned 23.2% on his investment. Determine how much money he has now.
Alika [10]
To figure out 23.2%, first figure out how much 1% is by dividing 1500 divided by 100=15

Next, multiply the 15(1%) by the 23.2% to figure out how much that is.
23.2 x 15 = 348

Now, you have to add thr investment ($348) to his originsl amount of money ($1500).
$1500 + $348 = $1848

Zach now has $1848
7 0
3 years ago
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