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Ymorist [56]
2 years ago
6

Solve for x: 3x + 4 = 9

Mathematics
2 answers:
coldgirl [10]2 years ago
3 0

Answer:

x=1.6 repeating. I hope this helped

MArishka [77]2 years ago
3 0

Answer:

5/3

Step-by-step explanation:

3x + 4 = 9 is the equation.

Subtract 4 from each side.

3x = 9 - 4

3x = 5

divide each side by 3

3x/3 = 5/3

The answer is 5/3 or 1 and 2/3

Rate as brainliest

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One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha
Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

V = 30 \times 30 \times 80

V = 72000 cm^3

to convert this to m^3 we know that 1m = 100cm

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)

the cm^3 cancel out.

V = \dfrac{72000}{100^3} m^3

V = 0.072\,m^3

by simply converting the side-lengths to meters beforehand can give you this answer directly:

V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3

it is given that 1 meter cube of water weighs about 2200 pounds.

1\,m^3 = 2200 \,\text{lb}

multiply both sides with 0.072 to find our answer:

1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}

0.072\,m^3 = 158.4 \,\text{lb}

hence the weight of the water in the tank would be 158.4 pounds!

3 0
3 years ago
You have 10 marbles in a bag: 3 blue, 2 green, 4 yellow, and 1 purple. If you close your eyes and choose a marble at random, wha
Naily [24]

Answer:

3/10

Step-by-step explanation:there are 10 marbles all together three blue ones

4 0
2 years ago
Read 2 more answers
Leona spent 5/8 of 2/3 of her allowance on magazines. What fraction of her total allowance did
PIT_PIT [208]

Answer:

leona spent 5/12 of her allowance

she had 1-5/12=7/12

please mark the brainliest

4 0
3 years ago
What percent of 140 is equal to 7% of 500​
blagie [28]

Answer:

49%

Step-by-step explanation:

7 percent of 500=35%

4 0
2 years ago
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This is for AP CALCULUS. I really need help on this. I’m trying to find the first and second derivative of these three functions
ale4655 [162]

Review Material:

\sqrt[n]{x^m} = x^{\frac{m}{n}}

\frac{d}{dx}[x^n]=nx^{n-1}\\

\frac{d}{dx}[\sin(x)]=\cos(x)\\

 \frac{d}{dx}[\cos(x)]=-\sin(x)\\

\frac{d}{dx}[constant]=0\\

Step-by-step explanation:

(a)

F(x) = -2\cos(x) +x^{\frac{4}{3}} -3e\\ \text{Note: 3e is a constant}\\F'(x) = 2\sin(x) + \frac{4}{3}x^{\frac{1}{3}}\\F''(x) = 2\cos(x) + \frac{4}{9}x^{-\frac{2}{3}}

(b)

F(x) = x^{-3} + \frac{1}{2}x^2-\sin(x)\\F'(x)=-3x^{-4} + x - \cos(x)\\F''(x) = 12x^{-5} + 1 + \sin(x)

(c)

F(x) = 2x^{-3}+x^{\frac{3}{4}}-4x\\F'(x) = -6x^{-4} + \frac{3}{4}x^{-\frac{1}{4}}-4\\F''(x)= 24x^{-5} - \frac{3}{16}x^{-\frac{5}{4}}

8 0
1 year ago
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