Hellppppp me its so confusing ????!!!!

Mathematics

1 answer:

melomori [17]3 years ago

3 0

I'm not sure but
A) 3 out of 20
B) 11 out of 100

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Mai biked

vovikov84 [41]

Answer: i cant understand the question but its either 2.25 if you mean how much more or 6.3 if you mean divided by

Step-by-step explanation:

6 0

2 years ago

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Help! Exponential Equation WITHOUT CALCULATOR

ale4655 [162]

$
1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

\\ \\ 2.( 2^{x})^{3} - (2^{-x}^) ^{3}= (2^{x} -2^{-x})(2^{2x}+2^{x}*2^{-x}+2^{-2x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+2^{x}*2^{-x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+1)
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})((2^{2x}+2^{-2x})+1)
$

$\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
\\ \\ 2^{3x}-2^{-3x} =76
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4 0

3 years ago

1. What is the radius<br> (1 Point)<br> 11 cm

mr_godi [17]

Given that we need to determine the radius of the circle.

<u>Radius:</u>

By definition of radius of circle, the radius is the length of the line which is drawn from the center of the circle to any point on the circle.

From the figure, we need to determine the radius of the circle.

As, we can see that, the distance from the center of the circle to the point on the circle is 11 cm.

Since, we know that, the radius is the distance from the center of the circle to the point on the circle then, the radius of the given circle is 11 cm

Thus, radius of the circle is 11 cm.

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3 years ago

The highest scores ata gymnastics meet were 9.675, 9.25,9.325 and 9.5. Write the scores in order from least to greatest.

Inga [223]

Starting with the least score it would be ; 9.25 , 9.325 , 9.5 , 9.675

4 0

3 years ago

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I also need help with 1,000,000 in exponential form , 10x10 , and 10,000 x10 please

xxMikexx [17]

Answer:

1,000,000= 10^6

10 times 10 is 100 (10^2)

10,000 times 10 is 100,000 (10^5)

7 0

3 years ago