Solve for x. 2cosxsinx=0

1 answer:

8 0

The first step would be to divde both sides by 2. then you would have to find where cos(x) times sin(x) would equal 0. to do that either cos(x) OR sin(x) would heve to be zero becasue any number times zero equals zero. n is an inteager (whole Number) cos(x) equals pi/2 plus pi times n. $2cos(x)sin(x)=0 \\ cos(x)sin(x)=0 \\ cos(x)=0 \\( \pi /2) + \pi n\\ sin(x)=0 \\ 0 + \pi n$

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Make x the subject of formular y=5√x+3-4

pochemuha

Answer:

x={(y+1) / 5}²

Step-by-step explanation:

y = 5√x +3 -4

⇒y = 5√x -1

add 1 on both sides

⇒ y + 1 = 5√x

divide both sides by 5

⇒(y+1) / 5 = (5√x) /5

⇒(y+1) / 5 = √x

now, square both sides

⇒{(y+1) / 5}² = (√x)²

∴{(y+1) / 5}² = x

8 0

3 years ago

Can someone help me with this, thanksssss

Effectus [21]

Answer:17

Step-by-step explanation:Follow pemdas.

Start with parentheses which is (5+2) which gives you 7.

Now next in Pemdas is Exponents. SO do 2 to power of 2 which is 4 .Then do 3 to the power of 3 which is 27.Next add 4 to 27 which is 31.so now do 7 times 2 is 14.Then take 31 and subtarct it from 14 which gives you 17.

Look at pic to see clearly how it was solved and the steps. I color code it to show the steps.