Answer: 20 cups of flour
Step-by-step explanation:
The sample of students required to estimate the mean weekly earnings of students at one college is of size 96.04.
For the population mean (μ) , we have the (1 - α)% confidence interval as:
X ± Zₐ / 2 + I / √n
margin of error = MOE = Zₐ / 2 ×I / √n
We are given:
σ = $10
MOE = $2
The critical value of z for 95% confidence level is
Zₐ / 2 = Zₓ = 1.96 ( for x as 0.025)
n = (1.96 (10))²
n = 96.04
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 96.04.
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I think the answe might be B
y = 25x + 50
$50 is a constant, whereas $25 is the daily rate and will vary
let x be the number of days rented, then
y = 25x + 50 ← in slope-intercept form
Answer:
3/5.
Since the numerator is an even number, you can simply remove half of it.
