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3 years ago

Does 3,4, and 5 make a right triangle or not a right triangle?

Mathematics

2 answers:

S_A_V [24]3 years ago

6 0

Answer:

I believe it does

Step-by-step explanation:

sorry if i am wrong

tatiyna3 years ago

3 0

Answer:

3,4,5 and 5 do make a right angle

Step-by-step explanation:

You might be interested in

How to solve this question

Viefleur [7K]

Answer:

7x+21 = 7x + 21

Step-by-step explanation:

7(x+3)=6-(-7x - 15)

L.H.S

=7(x+3)

=7x+21 (multiply 7 by (x+3))

R.H.S:

=6-(-7x - 15)

= 6+7x+15 (multiply the -ive sign in the bracket)

= 7x + 21 ( adding 15 and 6)

now compare the two sides

7x+21 = 7x + 21 hence we prove that L.H.S= R.H.S

4 0

3 years ago

On a factory floor, 65 out of every 140 toy robots is defective. What percent of the toy robots are defective? Round your answer

tester [92]

Answer:

65/140

as a percentage is 46.43

hundredth rounding

46.4

Step-by-step explanation:

8 0

3 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

A ping pong ball has a radius of 1 inch. Which value is closest to the volume of the ball? Use 3.14 for π.

zubka84 [21]

4.19 square inches.Hope i helped!

5 0

3 years ago

How do u guys solved this?

TEA [102]

Answer:

3 boxes

Step-by-step explanation:

First, we need to find the area of the whole square, so we can find out how much to subtract from. We can easily do this by multiplying 16 by 16, since it is a square.

16*16=256 square feet.

Now, we just need to find the area of the circular rug, and subtract it from 256 to find the area not covered by the rug that needs to be tiled. Since the sides of the rug touch each side of the floor, than the diameter will be the same as the side length of the square. Thus, the diameter is 16.

Now we can use the equation <em>A=pir^2 </em>or <em>Area=pi*radius squared</em> to find the area of the circle. The radius is halve of the diameter, so divide 16 by 2 to get the radius, or 8. Now all we have to do is square 8 and multiply it by 3.14.

8^2=64

Now multiply.

64*3.14=200.96.

The area of the circle is 200.96, so subtract 200.96 from 256.

256-200.96=55.04.

So they will need 3 boxes to cover the area left.

Hope this helps!

3 0

3 years ago