Does 3,4, and 5 make a right triangle or not a right triangle?

5x 2 +5x x 2 −1 What is an equivalent expression in lowest terms?

arsen [322]

Answer:

Step-by-step explanation:

Explanation:

Start by writing out your starting expression

x

2

−

5

x

2

+

5

x

−

14

−

x

+

3

x

+

7

Next, factor the denominator of the first fraction

x

2

+

5

x

−

14

x

2

+

7

x

−

2

x

−

14

x

(

x

−

2

)

+

7

(

x

−

2

)

(

x

−

2

)

(

x

+

7

)

Your expression is thus equivalent to

x

2

−

5

(

x

−

2

)

⋅

(

x

+

7

)

−

x

+

3

x

+

7

Since you have to subtract two fractions, you need to find the commonon denominator first. To do that, multiply the second fraction by

x

−

2

x

−

2

x

2

−

5

(

x

−

2

)

⋅

(

x

+

7

)

−

(

x

+

3

)

⋅

(

x

−

2

)

(

x

−

2

)

⋅

(

x

+

7

)

This will get you

x

2

−

5

−

(

x

+

3

)

(

x

−

2

)

(

x

−

2

)

(

x

+

7

)

x

2

−

5

−

x

2

−

x

+

6

(

x

−

2

)

(

x

+

7

)

=

1

−

x

(

x

−

2

)

(

x

+

7

)

5 0

2 years ago

86[]×[]=2325

forsale [732]

Answer:

235

Step-by-step explanation:

The square root of 55,225 is = 235

because,

235 x 235 = 55,225

8 0

3 years ago

Find the value of each variables in the parallelogram

xenn [34]

Answer:

A = 28

B = 87

Step-by-step explanation:

18 + 10 = 28

103 -16 = 87

4 0

3 years ago

James bought a cake that weighs 3 and 1 over 4 pounds. How many ounces does the cake weigh? Show your work. (5 points)

kolezko [41]

The weight of James cake in ounces is 52 ounces and the Pint of water dispensed in 20 seconds is 24 pints

<h3>Weight</h3>

Weight of cake = 3 1/4 pounds

1 pound = 16 ounces

Number of ounces the cake weigh = 3 1/4 pounds × 16 ounces

= 13/4 × 16

= (208) / 4

= 52 ounces

Water dispensed per second = 0.15 gallons
Number of seconds = 20 seconds

1 gallon = 4 quarts

0.15 gallon = 0.6 quarts

1 quart = 2 pints

0.6 quart = 1.2 pints

Pint of water dispensed in 20 seconds = 1.2 × 20

= 24 pints of water

Learn more about weight:

brainly.com/question/229459

#SPJ1

8 0

2 years ago

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago