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3 years ago

Plz help me on this i dont know how to do this!!!

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

x = -4

Step-by-step explanation:

Nikitich [7]3 years ago

7 0

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diane charges $10 for a house call plus $35 an hour for electrical work. if she made $150 on one job,how many hours did she work

salantis [7]

The equation would be 35x +10 = 150
35x =140 (subtraction property)
x = 4
Answer: she worked for 4 hours

8 0

3 years ago

Read 2 more answers

PLZ HELP! Use technology or a z-score table to answer the question.

Rashid [163]

Answer:

the answer would be A, or 5.3%

Step-by-step explanation:

you start by finding the z-score of 200, so 200-144.05 = 55.95/34.52 = 1.62 (rounded to the nearest ) Then you use a z-score table to find the probability that a customer will spend less than 200 dollars and subtract the decimal probability from one. then you convert the decimal probability to a percent and get 5.3%.

7 0

2 years ago

A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

3 years ago

Trey runs each lap in 6 minutes. He will run at least 30 minutes today. What are the possible numbers of laps he will run today?

vlada-n [284]

Answer:

5 laps

Step-by-step explanation:

30 ÷ 6 = n

n=5

8 0

3 years ago

A retailer buys a coat in bulk at a unit price of $45. The coat is marked up to 28% to sell in the store. What is the price of t

inessss [21]

The answer is $57.60

(The original price) 45+ 12.60 (28% of 45) = 57.60

6 0

3 years ago