Given P(A) = 0.8, P(B) = 0.51 and P(ANB) = 0.468, find the value of
1 answer:
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The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
Answer: C) y ≥ 3x - 2;
<u>Step-by-step explanation:</u>
Blue line:
y-intercept (b) = -2
slope (m) is 3 up, 1 right = 3
shading is above
⇒ y ≥ 3x - 2
Yellow line:
y-intercept (b) = 3
slope (m) is 1 up, 2 right =
shading is below