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ira [324]
3 years ago
7

Given P(A) = 0.8, P(B) = 0.51 and P(ANB) = 0.468, find the value of

Mathematics
1 answer:
masha68 [24]3 years ago
7 0

Answer:

Step-by-step explanation:

P(BA)=P(B)+P(A)-P(AnB)

= 0.51+0.8-0.468

=1.31-0.468

=0.842

P(BA) = 0.842

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Toys R us is having a 38% off sale on all of their backpacks.If a backpack normally cost 22.00 how much will it be on sale
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Answer:

$13.64

Step-by-step explanation:

The backpack is originally priced at $22. During the sale, the price would be 38% off which means you pay 62% of the original price. We can find this by multiplying by the percent 62 (converted into a decimal).


22(0.62)=13.64


The sale price at the sale is $13.64.

4 0
3 years ago
Find the equation of the function in the graph
andrezito [222]

Answer:

D

Step-by-step explanation:

it is a graph of x^{2}

5 0
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Harmon’s Jewelry Store receives a shipment of 500 jewelry pieces, but 15 pieces are damaged. At this rate, if Mrs. Harmon places
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She should expect 165 jewelry pieces to be damaged.

Step-by-step explanation:

5,500/500 = 11

11 x 15 = 165

5 0
3 years ago
Mary-Ann has $28, which is 2 1/3 as much money as Lona has. How much money dose Lona have?
pav-90 [236]

Answer:

12 dollars

Step-by-step explanation:

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6 0
2 years ago
A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph
belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(Smoker) =

P(S) = \dfrac{340}{2000}=0.17

P(emphysema) =

P(E) = \dfrac{25}{2000}= 0.0125

P(Smoker and emphysema) =

P(S\cap E) = \dfrac{21}{2000} = 0.0105

Two events A and B are said to be independent if

P(A\cap B)=P(A)\times P(B)

Checking conditions for independence:

P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0
3 years ago
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