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kodGreya [7K]
3 years ago
8

What is the slope of a line that is parallel to the line whose equation is 5y+2x=12?

Mathematics
2 answers:
murzikaleks [220]3 years ago
4 0

Answer:

Step-by-step explanation:

y=-2/5x

Molodets [167]3 years ago
3 0

Answer: -2/5

Step-by-step explanation: the slope of a line is the one that describes the direction and inclination of that line. When two lines are parallel, it means that they have the same slope. To determine the slope of a line, we need to isolate "y" and the slope will be the number that is with the "x," the procedure is shown as follow:

5y+2x=12

isolating y:

5y=12-2x

y=(12-2x)/5

the number that is with the "x" is -2/5 so that is the slope.

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Omar’s tank is 3/10 full. After he buys 11 gallons of gas, it is 4/5 full. How many gallons can Omar’s tank hold?
marin [14]

Answer:

22 gallons.

Step-by-step explanation:

11 gallons took you from 3/10 to 4/5 (same as 8/10).

so the 11 gallons was 5/10- or 1/2 the tank.

if 11 gallons =half a tank, then a full tank is 22 gallons

6 0
3 years ago
Show that f '(x) = g'(x) for all x in their domains. Can we conclude from the corollary below that f − g is constant? If f '(x)
spayn [35]

Answer:

Answer: 15 cm

Step-by-step explanation:

7 0
3 years ago
The total surface area of a closed cylinder is
Degger [83]

The maximum volume of the cylinder is 27147.355 at the maximum point  r = \frac{50}{\sqrt{3} } .

<h3>How do you find the maximum volume of the cylinder?</h3>

The formula for the volume of the cylinder v = \pir^{2}h, To find the maximum volume of the cylinder we apply the condition of maxima  \frac{\mathrm{d} v}{\mathrm{d} r} = 0.

Let r cm be the radius and h cm be the height of the closed cylinder.

Then, Total surface area of the cylinder = 2\pi r(r+h)

                                                        5000 = 2\pi r^{2} +2\pi rh

                                                             h =   \frac{5000-2\pi r^{2} }{2\pi rh} .............(1)

Volume of the cylinder v = \pi r^{2} h

Substitute the value of h in the above equation

\Rightarrow                                       = \pi r^{2} × \left [ \frac{5000-2\pi  r^{2}}{2\pi r} \right ]

\Rightarrow                                      = \frac{r}{2} ×  (5000-2\pi r^{2} )

\Rightarrow                                    v = 2500r-\pi r^{3} ..............(2)

Now, for the maximum volume of the cylinder  \frac{\mathrm{d} v}{\mathrm{d} r} = 0

\Rightarrow                                                            \frac{\mathrm{d} (2500r-\pi r^{3})}{\mathrm{d} r} = 0

\Rightarrow                                                                      3\pi r^{2} = 2500

\Rightarrow                                                                          r^{2} = \frac{2500}{3\pi }

\Rightarrow                                                                          r = \frac{50}{\sqrt{3\pi } }

Volume is maximum for  r = \frac{50}{\sqrt{3\pi } }  

Then, v = 2500r-\pi r^{3}

\Rightarrow              =  2500 \frac{50}{\sqrt{3\pi } } -\pi (\frac{50}{\sqrt{3\pi } } )^{3}                              

\Rightarrow             = \frac{125000}{\sqrt{3\pi } } - \frac{125000}{3\sqrt{3\pi } }

\Rightarrow             = \frac{125000}{\sqrt{3\pi } }×\frac{2}{3}

\Rightarrow             = \frac{250000}{3\sqrt{3\pi } }                                                              

\Rightarrow          v = 27147.355

Hence, The maximum volume of the cylinder is 27147.355 at the maximum point  r = \frac{50}{\sqrt{3} } .                                                

To learn more about total surface area and volume of the cylinder from the given link

brainly.com/question/16095729

#SPJ4                                                                                   

3 0
2 years ago
WILL GIVE BRAINLIEST ANSWER! ( CORRECT ANSWER )
Likurg_2 [28]
That would be 20/120 or reduced to 1/6, C.
5 0
3 years ago
Read 2 more answers
Please help me. I will give out brainliest.
strojnjashka [21]

area of quadrilateral (rhombus)=<u>4square units</u>

<u>:</u>

Solution given:

diagonal 1:AC=2 unit

diagonal 2:BD=4 unit

it looks like a rhombus

so

area of quadrilateral (rhombus)

=½*(diagonal 1*diagonal2)=½(2*4)=4 square units

8 0
3 years ago
Read 2 more answers
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