Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
You can start with the form
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:
7x +2y = 1
Answer:
The sign would be 784 ft. long.
Step-by-step explanation:
The sign would be painted across the total perimeter of the building.
- the distance across the front of the store is 294 feet
- the distance from the front to the back is one third of this distance = (1/3) × 294 = 98 ft.
The perimeter of a rectangular = 2(L + B)
L = length of the building = 294 ft.
B = Breadth of the building = 98 ft.
Perimeter of the chocolate factory that the Sign would be painted across = 2(294 + 98) = 784 ft.
Hope this Helps!!!