X*2 = 2x
Coefficient is 2.
The y-intercept would be (0,-3) and the x-intercept would be (-6,0).
Answer:
f(h(x)) = 2•(x²-1)² -4•(x²-1)
Answer:
Graph of a function on the domain negative 2, 6 and range negative 3, 4. Graph increases from negative 2, 3 until 2, 0 and from 4, negative 2.5 to 6, 4. Graph decreases from 2, 0 to 4, negative 2.5. There are x intercepts at 2, 0 and 4, negative 2.5.
Find the x-value where f attains its absolute minimum value on the closed interval from x = -2 to x = 6. Justify your answer.
Step-by-step explanation:
