<span>a = 1/2 x b x h

h = 3b

so 1/2 x b x 3b = (1/2)(3b^2) = 150

(150 x 2)/3 = b^2

100 = b^2

b = square root of 100 = 10

h = 3b = 3 x 10 = 30</span>

3 0

3 years ago

Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

7 0

3 years ago

Please help I have no idea what I'm doing with any of this!!

jasenka [17]

Answer: you are doing hell jesus

Step-by-step explanation:

6 0

3 years ago