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shepuryov [24]
4 years ago
6

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

days after inoculation?
Mathematics
2 answers:
meriva4 years ago
8 0

Answer:

2313

Step-by-step explanation:

A = P(1+r)^t

where A is the final amount, P is the initial amount, r is the rate, and t is time.

Here, P = 1000, r = 0.15, and t = 6.

A = 1000(1.15)^6

A ≈ 2313

Leto [7]4 years ago
7 0
<h2>Number of bacteria after 6 days is 2313</h2>

Step-by-step explanation:

Population after n days is given by

              P_n=P_0(1+r)^n

Initial population, P₀ = 1000

Increase rate, r = 15 % = 0.15

Number of days, n = 6

Substituting

             P_n=P_0(1+r)^n\\\\P_6=1000(1+0.15)^6\\\\P_6=1000(1.15)^6\\\\P_6=1000\times 2.313\\\\P_6=2313

Number of bacteria after 6 days = 2313

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<h3>Answers:</h3>
  • ST = 23
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====================================================

Explanation:

Focus on triangles SVT and UVT.

They are congruent triangles due to the fact that SV = VU and VT = VT. From there we can use the LL (leg leg) theorem for right triangles to prove them congruent.

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Therefore, RS = RU = 8

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-----------------------

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