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zepelin [54]
3 years ago
9

With some species of bamboo, you can actually see them grow. You could observe 30 centimeters of growth in just 1 3 of a day. At

what rate does this bamboo grow? Simplify your answer and write it as a proper fraction, mixed number, or whole number. centimeters per day
Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

90 centimetres per day

Step-by-step explanation:

Given that:

One of the Bamboo species growth can be seen.

Growth in \frac{1}{3} of a day = 30 cm

To find:

The growth per day in centimetres as a proper fraction, mixed number or whole number.

Solution:

If we are given that:

The growth of a bamboo tree is y centimetres in x number of days.

Then growth per day can be found by dividing the total growth of bamboo tree by the number of days.

Formula can be written as:

Growth per day = \frac{y}{x}

We are given that:

y = 30\ cm\\x = \frac{1}{3}\ days

Putting the values, we get:

\dfrac{30}{\frac{1}3}\\\Rightarrow \bold{90\ cm}

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If m∠2 = 130°, what is m∠6?
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Answer:

m<6 = 130°

Step-by-step explanation:

If m∠2 = 130°, what is m∠6?

Find the diagram attached

From the digram we can see that the vertical lines are parallel. Hence based on geometry;

m<2 = m<6 (corresponding angles)

Given m<2 = 130°, hence m<6 = 130°

8 0
3 years ago
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liraira [26]

Answer:

What is an equation of the line in point-slope form?

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Step-by-step explanation:

5 0
2 years ago
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An office building casts a 90 foot shadow. At the same time of day, a 5 foot woman standing near the building casts an 8 foot sh
Elenna [48]
Make a ratio: 
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Make sure shadow is in same location on both fractions (either numerator or denominator) </span>

x/90=5/8 

Cross multiply: 

8x=90x5 
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x=56.25 feet </span>

Therefore, the approximate height of the building to the nearest foot would be 56.25 feet.
<span>
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I hope my answer has come to your help. Thank you for posting your question here in Brainly.
8 0
3 years ago
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A pole that is 3.1m tall casts a shadow that is 1.46m long. At the same time, a nearby building casts a shadow that is 36.75m lo
Mademuasel [1]
You have to find the angle of sunlight and the pole , which then cast a shadow
length of the pole is equal to 3.1m
creating a hypotenuse of 4.52m
the angle will be
[email protected] = opposite side / hypotenuse
= 1.46/4.52
= 0.32 that's 18.66 °
now for the building sin18.66° = opposite/hypotenuse
0.32 = 36.75/ hypotenuse
hypotenuse = 114.84 m
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114.84*114.84 = 36.75*36.75 + x^2
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4 0
3 years ago
The following set of coordinates represents which figure? (1, 1), (5, 3), (7, 7), (3, 5) (4 points)
slamgirl [31]
Check the slopes 
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looks like a parallelogram or a rhombus 

if adjacent sides are equal its a rhombus

length betwee  pts 1 and 2  = sqrt(2^2 + 4^2) = sqrt20
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so it is a rhombus

8 0
3 years ago
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