All categories

3 years ago

What is the value of x in the equation 2x – 3 = 9 – 4x?

Mathematics

2 answers:

DENIUS [597]3 years ago

6 0

2*3 = 6 - 3 = 3
4*3 = 12 - 9 - 3
x= 3

nikdorinn [45]3 years ago

4 0

2x-3=9-4x
step 1: put like terms on the same side of the equation
2x+4x=9+3
step 2: add/subtract like term
6x=12
step 3: isolate the variable (x)
6x/6=12/6
final answer: x=2

You might be interested in

How many solutions does the system have? y = -2x-4 \\\\ y = 3x+3

lakkis [162]

Answer:

The system has one solution.

Step-by-step explanation:

We have two equations:

y = -2x - 4

y = 3x + 3

Equalling them:

y = y

-2x - 4 = 3x + 3

5x = -7

$x = -\frac{7}{5}$

And

$y = 3x + 3 = 3(-\frac{7}{5}) + 3 = \frac{-21}{5} + 3 = \frac{-21}{5} + \frac{15}{5} = -\frac{6}{5}$

Replacing in the other equation we should get the same result.

$y = -2x - 4 = -2(-\frac{7}{5}) - 4 = \frac{14}[5} - 4 = \frac{14}{4} - \frac{20}{5} = -\frac{6}{5}$

So the system has one solution.

3 0

3 years ago

What is the quotient? URGENT!!

jeyben [28]

Answer:

The answer is A.

Step-by-step explanation:

You have to multiply by converting the second fraction into upside down :

$\frac{4x + 1}{6x} \div \frac{x}{3x - 1}$

$= \frac{4x + 1}{6x} \times \frac{3x - 1}{x}$

$= \frac{(4x + 1)(3x - 1)}{x(6x)}$

$= \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} }$

$= \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} }$

5 0

2 years ago

If a and b are rational numbers and 5 +2 root 3/7+4 root3=a-b root 3;then a and b=

Usimov [2.4K]

Answer:

$\bold{a=5\,,\quad b=-4\frac27}$

Step-by-step explanation:

$5+\frac{2\sqrt3}7+4\sqrt3=5+\frac27\sqrt3+4\sqrt3=5+4\frac27\sqrt3=5-(-4\frac27)\sqrt3$

6 0

3 years ago

Can someone help me with the middle question?

kotegsom [21]

You should do 1.0 divided by 7 and the answer would be 7

7 0

3 years ago

The sum of two number is 45.if one of them is 27 ,find another

tekilochka [14]

Answer:

is 18

Step-by-step explanation:

simple you just subtract 27 for the original number

8 0

2 years ago

Read 2 more answers