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Yuki888 [10]
3 years ago
14

Help plz will mark brainliest :)​

Mathematics
1 answer:
avanturin [10]3 years ago
5 0

Answer:

c

Step-by-step explanation:

subtract b from both sides

divide by x

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A cyclist is riding from the city to the country. She rides 20 miles each hour. At the beginning of the 1 st hour, she is 10 mil
strojnjashka [21]

Answer:

450miles

Step-by-step explanation:

Because she is riding at 20 miles per houre means that she ride 450 miles in 5 houre.

7 0
2 years ago
Solve for x please, explantion is not nesscary but it would help me
Ber [7]

Answer:

x = 100 degrees

Step-by-step explanation:

There are 360 degrees total in this figure. Since 160 is already shown, we can subtract it from 360 to solve for x. 360 - 160 = 200. So, 200 degrees is split among the remaining values, which are 2 x's. Since each x has the same value, we can divide 200 evenly among the two of them. 200/2 = 100. So, x = 100.

P.S.: Sorry if this is long-winded, I haven't taken geometry in a while. I hope I explained it well enough for you and other Brainly users.

7 0
3 years ago
Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
4 years ago
A large university accepts 50​% of the students who apply. Of the students the university​ accepts, 35​% actually enroll. If 10,
lara31 [8.8K]

Answer:

3,500 students

Equation:

0.35 x 10,000 = 3,500

8 0
3 years ago
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