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Serga [27]
3 years ago
6

Find the x- and y-intercepts of the line (-6.-6), (2, -4) The x-intercept is

Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:

x-int = 18

y-int = -9/2

Step-by-step explanation:

Use slope-intercept form y=mx + b

To find the slope, substitute the two points into the slope formula and solve.

m  = \frac{y2 - y1}{x1 - x1} \\m  = \frac{-4 - (-6)}{2 - (-6)} \\m = \frac{2}{8}\\m= \frac{1}{4}

Substitute a random point (2,-4) and m=1/4 into slope-intercept form

y = mx+b

-4 = 1/4 (2) + b

-4 = 2/4 + b

-4 = 1/2 + b

Isolate b to solve

b = -4 - 1/2

b = -8/2 - 1/2

b = -9/2    <= this is the y-intercept

b is the y-intercept in slope-intercept form

Substitute b= -9/2 and m=1/4 to get the equation of the line.

y = 1/4 x - 9/2

Substitute y for 0 to find the x intercept

y = 1/4 x - 9/2

0 = 1/4 x - 9/2

9/2 = 1/4 x

x = (9/2) / (1/4)

x = (9/2) X (4/1)

x = 36/2

x = 18

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2.75 + negative 1.5
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Answer:

1.25

Step-by-step explanation:

type in your calculator:

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you should get the same answer

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4 years ago
A rectangle has sides of length 6.1cm and 8.1cm correct to one decimal place.
tamaranim1 [39]
The area is 49.41

6.1x8.1
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3 years ago
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Sara has $50 in her wallet in $5 and $20 bills. Create a linear equation (with
77julia77 [94]

Answer:

<em>0 $20 bills and 10 $5 bills</em>

<em>1 $20 bills and 6 $5 bills</em>

<em>2 $20 bills and 2 $5 bills</em>

Step-by-step explanation:

<u>Equations</u>

Let's set:

x=number of $5 bills

y=number of $20 bills

The total amount Sara has is given by

5x+20y

And we know it's equal to $50, thus:

5x+20y=50

Dividing by 5

x+4y=10

We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.

Solving for x:

x=10-4y

Since both x and y are integers and cannot be negative:

10-4y≥0

Swapping sides:

4y≤10

Dividing by 4:

y≤2.5

Thus, y can only have the values {0,1,2}

For y=0

x=10-4*0=10

x=10

For y=1

x=10-4*1=6

x=6

For y=2

x=10-4*2=2

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1 $20 bills and 6 $5 bills

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4 0
3 years ago
Use the Law of Cosines to find the missing angle.<br><br> Find m∠A to the nearest tenth of a degree.
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Firstly, we can look at our givens,

a = 17

b = 22

c = 30

And we are looking for m∠A

a^2=b^2 +c^2 -2bc (cosA) Is the Law of Cosines. Now we can solve for our unknown, m∠A. This will give us

A = cos^{-1} (\frac{-a^2+b^2+c^2}{2bc})

Now we can substitute in our given variables.

A= cos^{-1} (\frac{-(17^2)+27^2+30^2}{2(27)(30)} )

Then we can plug this into our calculator which will give us

34.19185257 degrees

Now we just have to round to the nearest tenth

This means that the answer is 34.2 degrees

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