What is the standard form of this equation of a circle?
2 answers:
<span>x² + y² + 14x − 4y − 28 = 0
x² +14x +y² - 4y =28
x²+2*7x +7² -7² + y² - 2*2y +2² - 2² = 28
(x+7)² + (y-2)² -7²-2² =28
</span>(x+7)² + (y-2)²=28+49+4
(x+7)² + (y-2)² =81 is the answer.
(x2 + 14x + 49) + (y2 − 4y + 4) − 28 = 49 + 4
(x + 7)2 + (y − 2)2 − 28 = 49 + 4
(x + 7)2 + (y − 2)2 = 49 + 4 + 28 = 81.
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so use pythagorean theorm
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