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3 years ago

8

The ______ property of equality stated that if you divide both side by an equation by the same non cero number , the two sides w

ill remain equal

1 answer:

sattari [20]3 years ago

3 0

Answer:

division

Step-by-step explanation:

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Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.

Maslowich

Answer:

16 pi cubic units

Step-by-step explanation:

Given that a region is bounded by

$f(x)=√x, y=0, x=1, x=4$

And the region is rotated about x axis.

We can find that here radius would be y value and height would be dx

So volume would be as follows:

If f(x) is rotated about x axis volume

= $\pi \int\limits^b_a {y^2} \, dx \\=\pi \int\limits^4_1 {x} \, dx\\=\pi *x^2 ^4_1\\= \pi*16-1\\=15\pi$

cubic units.

4 0

3 years ago

Write 5^4 in standard form

AfilCa [17]

Answer:

625

600+20+5

Step-by-step explanation:

<em>Parenthesis</em>

<em>Exponent</em>

<em>Multiply</em>

<em>Divide</em>

<em>Add</em>

<em>Subtract</em>

<em>From left to right.</em>

<em>Do exponent first.</em>

<em> $5^4=5*5*5*5=625$ </em>

<em>Standard form of 5^4 is: ⇒ 600+200+5</em>

<em>625 is the correct answer.</em>

<em>600+200+5 is the correct answer.</em>

4 0

3 years ago

Read 2 more answers

What properties would you use to find the answer 345+130?

kondaur [170]

Addition property of equality

6 0

3 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

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PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP:))))

MrRissso [65]

Answer:

Step-by-step explanation:

(3x + 6) + (3x + 6) = 6x + 12

(-2x - 1) + (-2x - 1) = -4x - 2

6x + 12 -4x - 2

2x + 10

5 0

3 years ago

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