The point in between is (1,2)
Answer:
The required expression is
.
The value of the expression when y=20 is 2.
Step-by-step explanation:
Consider the provided phase.
3 less than the quotient of a number y and 4
The quotient of a number y and 4 can be written as: 
Now 3 less than the quotient of a number y and 4 can be written as:

Hence, the required expression is
.
Now evaluate when y=20.
Substitute y=20 in above expression.



Hence, the value of the expression when y=20 is 2.
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Answer:
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Step-by-step explanation:
Answer:
Answer: y=2x+13.
Step-by-step explanation:
Your input: find the equation of the line perpendicular to the line y=5/2−x/2 passing through the point (−4,5).
The equation of the line in the slope-intercept form is y=5/2−x/2.
The slope of the perpendicular line is negative inverse: m=2.
So, the equation of the perpendicular line is y=2x+a.
To find a, we use the fact that the line should pass through the given point: 5=(2)⋅(−4)+a.
Thus, a=13.
Therefore, the equation of the line is y=2x+13.
Answer: y=2x+13.