Question

The area of a rectangle is 27ft squared, and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle.

Answer 1

Answer:

width =4.5ft

length=6ft

Step-by-step explanation:

w = x

L = 2x-3

area = L*w

27 = x(2x-3)

$27=2x^{2} -3x$

$2x^{2} -3x-27=0$

$2x^{2} +6x-9x-27=0$

2x(x+3)-9(x+3)=0

(2x-9)(x+3)=0

2x-9=0

2x=9

x=9/2

x=4.5

L=2x-3=2*4.5-3 =9-3=6