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Kryger [21]
3 years ago
14

Find the slope intercept form of the liner function using the points (-6,6) and (-2,4) Show all work

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

y = - \frac{1}{2} x + 3

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, 6 ) and (x₂, y₂ ) = (- 2, 4 )

m = \frac{4-6}{-2+6} = \frac{-2}{4} = - \frac{1}{2}

y = - \frac{1}{2} x + c is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 2, 4 ), then

4 = 1 + c ⇒ c = 4 - 1 = 3

y = - \frac{1}{2} x + 3 ← in slope-intercept form


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<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

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\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

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\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

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