Ask question

Ask question

All categories

aleksklad [387]

2 years ago

9

Anna enjoys dinner with her family at a restaurant in Washington, D.C. She leaves a 15% tip on the price of her meal. She also h

as to pay a 10% sales tax on her meal, which is calculated on the pre-tip amount. She spends a total of $27.50 for dinner, including tax and tip. What is the cost of her dinner without tax and tip? Show your work.

1 answer:

AnnZ [28]2 years ago

3 0

Answer:

$22

Step-by-step explanation:

tax and the tip increase the price paid for the meal

she paid 15 + 10 = 25% more than the price of her meal

p = original price

1.15 x p = 27,50

p = 27.50 / 1.15 = 22

You might be interested in

A highway map of Ohio has a coordinate grid superimposed on top of the state. Springfield is at point (1, –4) and Columbus is at

aniked [119]

Find the midpoint of (1,-4) and (7,1) to find the rest stop. To do this add the x values and divide by 2, then add the y values and divide by 2. (4,-1.5) is the midpoint.
To find the distance, use the distance formula then multiply the result by 5.38. The distance is 42 miles

8 0

3 years ago

What can you say about the y-help urgent!!!

weeeeeb [17]

The correct answer is ( A )

let me know if you need explanation.

3 0

2 years ago

How does the slope of g(x) compare to the slope of f(x)?

Maru [420]

Answer:

The answer is 'The slope of g(x) is less than the slope of f(x)'

Step-by-step explanation:

Given the graphs of f(x) and g(x). we have to compare the slops of these two.

The graph of f(x) passes through the points (1,0) and (2,2)

∴ $\text{The slope of f(x)=}\frac{y_2-y_1}{x_2-x_1}=\frac{2-0}{2-1}=2$

The graph of g(x) passes through the points (0,2) and (2,3)

∴ $\text{The slope of g(x)=}\frac{y_2-y_1}{x_2-x_1}=\frac{3-2}{2-0}=\frac{1}{2}$

As $\frac{1}{2}$

This shows that the

The slope of g(x) is less than the slope of f(x).

8 0

2 years ago

Read 2 more answers

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

$m_ {1} * m_ {2} = - 1$

The given line is:

$5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3$

So we have:

$m_ {1} = \frac {5} {2}$

We find $m_ {2}:$ $m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}$

So, a line perpendicular to the one given is of the form:

$y = - \frac {2} {5} x + b$

We substitute the given point to find "b":

$-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2$

Finally we have:

$y = - \frac {2} {5} x-2$

In point-slope form we have:

$y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)$

ANswer:

$y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)$

3 0

2 years ago

Read 2 more answers

Week 1 2 3 4 5 Water Level (inches) − 1 1 4 1 3 8 2 1 2 − 1 5 8 − 1 3 4 Between which two weeks did the water level change the m

suter [353]

Answer:

The water level change the most in week 3 and week 4

The change = -370 inches

Step-by-step explanation:

Given - Week 1 2 3 4 5

Water Level (inches) − 1 1 4 1 3 8 2 1 2 -1 5 8 -1 3 4

To find - Between which two weeks did the water level change the most? Calculate the change .

Proof -

The formula for change in water level with respect to week be-

Rate of Change in Water Level = Difference in water level / Difference in weeks

Now,

For week 1 and week 2

Rate of change in water level = $\frac{138 - 114}{2 - 1}$ = $\frac{24}{1}$ = 24 inches

Now,

For week 1 and week 3

Rate of change in water level = $\frac{212 - 114}{3 - 1}$ = $\frac{98}{2}$ = 49 inches

Now,

For week 1 and week 4

Rate of change in water level = $\frac{-158 - 114}{4 - 1}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 1 and week 5

Rate of change in water level = $\frac{-134 - 114}{5 - 1}$ = $-\frac{248}{4}$ = -62 inches

Now,

For week 2 and week 3

Rate of change in water level = $\frac{212 - 138}{3 - 2}$ = $\frac{74}{1}$ = 74 inches

Now,

For week 2 and week 4

Rate of change in water level = $\frac{-158 - 138}{4 - 2}$ = $-\frac{296}{2}$ = -148 inches

Now,

For week 2 and week 5

Rate of change in water level = $\frac{-134 - 138}{5 - 2}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 3 and week 4

Rate of change in water level = $\frac{-158 - 212}{4 - 3}$ = $-\frac{370}{1}$ = -370 inches

Now,

For week 3 and week 5

Rate of change in water level = $\frac{-134 - 212}{5 - 3}$ = $-\frac{346}{2}$ = 173 inches

Now,

For week 4 and week 5

Rate of change in water level = $\frac{-134 + 158}{5 - 4}$ = $\frac{24}{1}$ = 24 inches

∴ we get

The water level change the most in week 3 and week 4

The change = -370 inches

Note :

The highest change means which temperature goes the most change in water level. It can be negative also.

So, We have to take the modulus and then find the highest number.

Here, 370 > 173

So, Highest change occurs in Week 3 and Week 4 but not in Week 3 and Week 5.

7 0

2 years ago