Question

0. A 5-kg block of ice is at a temperature of -27 °C. How much heat must be added to the ice to produce 5 kg of liquid water with a final temperature of 35 o C?

Answer 1

Answer:

Q = 2687130 J

Explanation:

m = mass of block of ice = 5 kg

$T_{i}$ = Initial temperature of ice block = - 27 °C

$T_{f}$ = final temperature of water = 35 °C

$c_{i}$ = specific heat of ice = 2108 J/(Kg °C)

$L$ = Latent heat of fusion of ice = 334000 J/kg

$c_{w}$ = specific heat of water = 4186 J/(Kg °C)

Heat added is given as

$Q = m c_{i}(0 - T_{i})+ mL + m c_{w}(T_{f} - 0)$

$Q = (5) (2108)(0 - (-27))+ (5)(334000) + (5) (4186)(35 - 0)$

$Q = 2687130 J$