Answer:
v = √k/m x
Explanation:
We can solve this exercise using the energy conservation relationships
starting point. Fully compressed spring
Em₀ = = ½ k x²
final point. Cart after leaving the spring
= K = ½ m v²
Em₀ = Em_{f}
½ k x² = ½ m v²
v = √k/m x
Answer:
400 N
Explanation:
From the question,
F = kmm'/r²........................ Equation 1
Where F = gravitation force, m and m' = mass 1 and mass 2 respectively, r = distance between the masses.
Given; F = 800 N
Substitute these values into equation 1
800 = kmm'/r².............. Equation 2
If the distance is doubled (2r), and one of the mass is doubled (2m), The new force is
F' = k(2m)(m')/(2r)²
F' = 2kmm'/4r²
F' = kmm'/2r²................. Equation 3
Comparing equation 2 and equation 3
F' = F/2............................ Equation 4
Substitute the value of F into equation 4
F' = 800/2
F' = 400 N
Answer:c will be answer
Explanation:Because u know F=ma so if we wanna know m then we should move a on left side and it will be in divide with f after moving on left side so
M=F/A
Answer:
1) A = 0.25 m², 2) V = 0.5 m³, 3) m = 1500 kg, 4) W = 14700 N,
5) P = 58800 Pa
Explanation:
1) The area of the base is square
A = L²
A = 0.5²
A = 0.25 m²
2) The block is a parallelepiped
V = A h
V = 0.25 2
V = 0.5 m³
3) Density is defined
rho = m / V
m = rho V
m = 3000 0.5
m = 1500 kg
4) The weight of a body is
W = mg
W = 1500 9.8
W = 14700 N
5) The pressure is
P = F / A
in this case the force is equal to the weight of the body
P = 14700 / 0.25
P = 58800 Pa