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3 years ago

Identify the reflection of the figure with vertices E(8,4), F(-16,-8), and G(24,-16) across the y-axis.

Mathematics

1 answer:

Dafna1 [17]3 years ago

6 0

Answer:

$\boxed{\text{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}$

Step-by-step explanation:

When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

E (8,4) ⟶ E' (-8,4)

F (-16,-8) ⟶ F' (16,-8)

G (24,-16) ⟶ G' (-24,-16)

$\text{The reflected figure has coordinates } \boxed{\textbf{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}$

The figure EFG and its reflection E'F'G' are shown in the diagram below.

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If the area of a right-angled triangle is 47 56 cm and its height is 11.6 cm. finds its base.

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820

Step-by-step explanation:

Hi so if your area is 4756, the base would be 820

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3 years ago

How many solutions does 9 - 5x = 8 - 3x - 1 -2x have?

Burka [1]

Answer:

D) Zero solutions

Step-by-step explanation:

9 - 5x = 8 - 3x - 1 - 2x

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3 years ago

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21 years

Step-by-step explanation:

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3 years ago

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2 years ago

Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5

zaharov [31]

Answer:

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

$\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}$ or $\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}$

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

$\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}$

Therefore, the solution is 31.

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Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as $\displaystyle \large{a_{n-1} \cdot r = a_n}$ meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as: