Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:
A=30,32,44,48
B=22,34
intersect=26
numbers going outside is 24,28,36,38,40,42,46
b) 1/14
Step-by-step explanation:
a)The numbers that will go into the A bracket will be 30,32,44 and 48. The numbers that will go into the B bracket will be 22 and 34. The number that will go into the intersect will only be 26. And finally the numbers going on the outside of the venn diagram will be 24,28,36,38,40,42,46.
b)The answer will be 1/14
Answer:-3x(3x^2+1)
Step-by-step explanation:
To solve -3x^3-3x
Factorise the common factors
-3x(3x^2+1)
Answer:
-20i^2 + 22i - 6
Step-by-step explanation:
(3 - 5i)(-2 + 4i) = -6 + 10i + 12i - 20i^2 = -20i^2 + 22i - 6
if you want to go further,
-20i^2 + 22i - 6 = -2(10i^2 - 11i + 3)
