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Goryan [66]
3 years ago
13

In how many ways can 8 people be seated in a row if there are no restrictions on the seating arrangement?

Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

a ) P₈  =  40320

b) P = 576

c) P =   1440

d) P =  24

Step-by-step explanation:

a )  8 people sitting in a row without restrictions

simple  Total ways  =  P₈  =  8!

P₈  =  8*7*6*5*4*3*2*1

P₈  =  40320

b) There are 4 men and 4 women  and no two men or 2 women can sit next to each other

Let  letters e women  and numbers  be men we have something like this

1  a  2  b  3  c  4  d

So we have the permutations of the four digits (men)

P₄  =  4!  

P₄  =  4*3*2*1   =  24

And the permutations of the 4 women too  equal to 24

Then total ways of sitting in a row in this case is

P = 24*24  = 576

c) There are 5 men and they have to sit next to each other

In this case we have 2 groups:  

Group 1    5 men                        Group  2    3  women

We have two groups and the ways are

group men first                group of women second         1  way

group of women first       group of  men second             2  way

Permutations within men group

P₅  =  5!    =  5*4*3*2*1    

P₅  =   120

Permutations within the women group

P₃  = 3!     =  3*2*1  

P₃  = 6

Total ways case c)   T = 6*120*2  =

P(c)  =  1440

d) There are four couples and each couple must be together

P₄ =  4!  =  4*3*2*1

P₄ =  24

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